Solution of the Minute

October 25th, 2009 by ben Leave a reply »

“Lewis and Carol travel together on a road from A to B, then return on the same road, with the entire trip taking 3 hours. Sometimes that road goes uphill, sometimes downhill, and sometimes it is level. When the road goes uphill, their rate is 40 mph; downhill their rate is 60 mph; on level road, their rate is x mph.”

Even if you were given a numerical value for x, the distance from A to B would (in most cases) not be uniquely determined. But there is one value for x that would determine that distance uniquely. Compute this value of x [Note: uphill going is downhill returning!]

Credits – Southern California ARML, Oct. 2009, Team round

Original post here.

Solution follows.
Let l be the distance spent on level road, and let s be the distance spent on sloped road (which way, uphill or downhill, doesn’t matter because it’ll be reversed when they turn back).

s \cdot \dfrac{1}{40} + s \cdot \dfrac{1}{60} + 2 l \cdot \dfrac{1}{x} = 3

This equation can be simplified to:

\dfrac{s}{24} + \dfrac{2l}{x} = 3

Or, multiplying both sides by 24:

s + \dfrac{48l}{x} = 72

The only value of x for which s+l can be uniquely defined is x=\boxed{48}.


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